x^2-x(5+5i)+25i=0

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Solution for x^2-x(5+5i)+25i=0 equation: 


Simplifying
x2 + -1x(5 + 5i) + 25i = 0
x2 + (5 * -1x + 5i * -1x) + 25i = 0

Reorder the terms:
x2 + (-5ix + -5x) + 25i = 0
x2 + (-5ix + -5x) + 25i = 0

Reorder the terms:
25i + -5ix + -5x + x2 = 0

Solving
25i + -5ix + -5x + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '5x' to each side of the equation.
25i + -5ix + -5x + 5x + x2 = 0 + 5x

Combine like terms: -5x + 5x = 0
25i + -5ix + 0 + x2 = 0 + 5x
25i + -5ix + x2 = 0 + 5x
Remove the zero:
25i + -5ix + x2 = 5x

Add '-1x2' to each side of the equation.
25i + -5ix + x2 + -1x2 = 5x + -1x2

Combine like terms: x2 + -1x2 = 0
25i + -5ix + 0 = 5x + -1x2
25i + -5ix = 5x + -1x2

Reorder the terms:
25i + -5ix + -5x + x2 = 5x + -5x + -1x2 + x2

Combine like terms: 5x + -5x = 0
25i + -5ix + -5x + x2 = 0 + -1x2 + x2
25i + -5ix + -5x + x2 = -1x2 + x2

Combine like terms: -1x2 + x2 = 0
25i + -5ix + -5x + x2 = 0

The solution to this equation could not be determined.

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